3.746 \(\int \frac {x^{13/2}}{(a+c x^4)^2} \, dx\)

Optimal. Leaf size=308 \[ \frac {7 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {7 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {x^{7/2}}{4 c \left (a+c x^4\right )} \]

[Out]

-1/4*x^(7/2)/c/(c*x^4+a)+7/16*arctan(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(1/8)/c^(15/8)-7/16*arctanh(c^(1/8)*x^(1
/2)/(-a)^(1/8))/(-a)^(1/8)/c^(15/8)+7/32*arctan(-1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)^(1/8))/(-a)^(1/8)/c^(15/8)*2^(
1/2)+7/32*arctan(1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)^(1/8))/(-a)^(1/8)/c^(15/8)*2^(1/2)+7/64*ln((-a)^(1/4)+c^(1/4)*
x-(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(1/8)/c^(15/8)*2^(1/2)-7/64*ln((-a)^(1/4)+c^(1/4)*x+(-a)^(1/8)*c^(1
/8)*2^(1/2)*x^(1/2))/(-a)^(1/8)/c^(15/8)*2^(1/2)

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Rubi [A]  time = 0.27, antiderivative size = 308, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 12, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {288, 329, 301, 297, 1162, 617, 204, 1165, 628, 298, 205, 208} \[ \frac {7 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {7 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {x^{7/2}}{4 c \left (a+c x^4\right )} \]

Antiderivative was successfully verified.

[In]

Int[x^(13/2)/(a + c*x^4)^2,x]

[Out]

-x^(7/2)/(4*c*(a + c*x^4)) - (7*ArcTan[1 - (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(16*Sqrt[2]*(-a)^(1/8)*c^(15
/8)) + (7*ArcTan[1 + (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(16*Sqrt[2]*(-a)^(1/8)*c^(15/8)) + (7*ArcTan[(c^(1
/8)*Sqrt[x])/(-a)^(1/8)])/(16*(-a)^(1/8)*c^(15/8)) - (7*ArcTanh[(c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(16*(-a)^(1/8)*
c^(15/8)) + (7*Log[(-a)^(1/4) - Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[x] + c^(1/4)*x])/(32*Sqrt[2]*(-a)^(1/8)*c^(15/
8)) - (7*Log[(-a)^(1/4) + Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[x] + c^(1/4)*x])/(32*Sqrt[2]*(-a)^(1/8)*c^(15/8))

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 288

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^
n)^(p + 1))/(b*n*(p + 1)), x] - Dist[(c^n*(m - n + 1))/(b*n*(p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 298

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b),
2]]}, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &
&  !GtQ[a/b, 0]

Rule 301

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(
a/b), 2]]}, Dist[s/(2*b), Int[x^(m - n/2)/(r + s*x^(n/2)), x], x] - Dist[s/(2*b), Int[x^(m - n/2)/(r - s*x^(n/
2)), x], x]] /; FreeQ[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LeQ[n/2, m] && LtQ[m, n] &&  !GtQ[a/b, 0]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {x^{13/2}}{\left (a+c x^4\right )^2} \, dx &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}+\frac {7 \int \frac {x^{5/2}}{a+c x^4} \, dx}{8 c}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}+\frac {7 \operatorname {Subst}\left (\int \frac {x^6}{a+c x^8} \, dx,x,\sqrt {x}\right )}{4 c}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}-\frac {7 \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a}-\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{8 c^{3/2}}+\frac {7 \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{8 c^{3/2}}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}-\frac {7 \operatorname {Subst}\left (\int \frac {1}{\sqrt [4]{-a}-\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{16 c^{7/4}}+\frac {7 \operatorname {Subst}\left (\int \frac {1}{\sqrt [4]{-a}+\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{16 c^{7/4}}-\frac {7 \operatorname {Subst}\left (\int \frac {\sqrt [4]{-a}-\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{16 c^{7/4}}+\frac {7 \operatorname {Subst}\left (\int \frac {\sqrt [4]{-a}+\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{16 c^{7/4}}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}+\frac {7 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {7 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}+\frac {7 \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{32 c^2}+\frac {7 \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{32 c^2}+\frac {7 \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}+2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}-2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}+\frac {7 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {7 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}+\frac {7 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}\\ &=-\frac {x^{7/2}}{4 c \left (a+c x^4\right )}-\frac {7 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt {2} \sqrt [8]{-a} c^{15/8}}+\frac {7 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}-\frac {7 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{16 \sqrt [8]{-a} c^{15/8}}+\frac {7 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}-\frac {7 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{32 \sqrt {2} \sqrt [8]{-a} c^{15/8}}\\ \end {align*}

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Mathematica [C]  time = 0.04, size = 43, normalized size = 0.14 \[ \frac {2 x^{7/2} \left (\frac {\, _2F_1\left (\frac {7}{8},2;\frac {15}{8};-\frac {c x^4}{a}\right )}{a}-\frac {1}{a+c x^4}\right )}{c} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(13/2)/(a + c*x^4)^2,x]

[Out]

(2*x^(7/2)*(-(a + c*x^4)^(-1) + Hypergeometric2F1[7/8, 2, 15/8, -((c*x^4)/a)]/a))/c

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fricas [B]  time = 0.65, size = 535, normalized size = 1.74 \[ -\frac {16 \, x^{\frac {7}{2}} + 28 \, \sqrt {2} {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {\sqrt {2} a c^{13} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} - a c^{11} \left (-\frac {1}{a c^{15}}\right )^{\frac {3}{4}} + x} c^{2} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} - \sqrt {2} c^{2} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} + 1\right ) + 28 \, \sqrt {2} {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {-\sqrt {2} a c^{13} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} - a c^{11} \left (-\frac {1}{a c^{15}}\right )^{\frac {3}{4}} + x} c^{2} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} - \sqrt {2} c^{2} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} - 1\right ) - 7 \, \sqrt {2} {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \log \left (\sqrt {2} a c^{13} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} - a c^{11} \left (-\frac {1}{a c^{15}}\right )^{\frac {3}{4}} + x\right ) + 7 \, \sqrt {2} {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \log \left (-\sqrt {2} a c^{13} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} - a c^{11} \left (-\frac {1}{a c^{15}}\right )^{\frac {3}{4}} + x\right ) + 56 \, {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {-a c^{11} \left (-\frac {1}{a c^{15}}\right )^{\frac {3}{4}} + x} c^{2} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} - c^{2} \sqrt {x} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}}\right ) - 14 \, {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \log \left (a c^{13} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} + \sqrt {x}\right ) + 14 \, {\left (c^{2} x^{4} + a c\right )} \left (-\frac {1}{a c^{15}}\right )^{\frac {1}{8}} \log \left (-a c^{13} \left (-\frac {1}{a c^{15}}\right )^{\frac {7}{8}} + \sqrt {x}\right )}{64 \, {\left (c^{2} x^{4} + a c\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(13/2)/(c*x^4+a)^2,x, algorithm="fricas")

[Out]

-1/64*(16*x^(7/2) + 28*sqrt(2)*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*arctan(sqrt(2)*sqrt(sqrt(2)*a*c^13*sqrt(x)*
(-1/(a*c^15))^(7/8) - a*c^11*(-1/(a*c^15))^(3/4) + x)*c^2*(-1/(a*c^15))^(1/8) - sqrt(2)*c^2*sqrt(x)*(-1/(a*c^1
5))^(1/8) + 1) + 28*sqrt(2)*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*arctan(sqrt(2)*sqrt(-sqrt(2)*a*c^13*sqrt(x)*(-
1/(a*c^15))^(7/8) - a*c^11*(-1/(a*c^15))^(3/4) + x)*c^2*(-1/(a*c^15))^(1/8) - sqrt(2)*c^2*sqrt(x)*(-1/(a*c^15)
)^(1/8) - 1) - 7*sqrt(2)*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*log(sqrt(2)*a*c^13*sqrt(x)*(-1/(a*c^15))^(7/8) -
a*c^11*(-1/(a*c^15))^(3/4) + x) + 7*sqrt(2)*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*log(-sqrt(2)*a*c^13*sqrt(x)*(-
1/(a*c^15))^(7/8) - a*c^11*(-1/(a*c^15))^(3/4) + x) + 56*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*arctan(sqrt(-a*c^
11*(-1/(a*c^15))^(3/4) + x)*c^2*(-1/(a*c^15))^(1/8) - c^2*sqrt(x)*(-1/(a*c^15))^(1/8)) - 14*(c^2*x^4 + a*c)*(-
1/(a*c^15))^(1/8)*log(a*c^13*(-1/(a*c^15))^(7/8) + sqrt(x)) + 14*(c^2*x^4 + a*c)*(-1/(a*c^15))^(1/8)*log(-a*c^
13*(-1/(a*c^15))^(7/8) + sqrt(x)))/(c^2*x^4 + a*c)

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giac [B]  time = 0.74, size = 486, normalized size = 1.58 \[ -\frac {x^{\frac {7}{2}}}{4 \, {\left (c x^{4} + a\right )} c} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{16 \, a c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (-\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{16 \, a c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{16 \, a c \sqrt {2 \, \sqrt {2} + 4}} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (-\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{16 \, a c \sqrt {2 \, \sqrt {2} + 4}} - \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{32 \, a c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (-\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{32 \, a c \sqrt {-2 \, \sqrt {2} + 4}} - \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{32 \, a c \sqrt {2 \, \sqrt {2} + 4}} + \frac {7 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (-\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{32 \, a c \sqrt {2 \, \sqrt {2} + 4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(13/2)/(c*x^4+a)^2,x, algorithm="giac")

[Out]

-1/4*x^(7/2)/((c*x^4 + a)*c) + 7/16*(a/c)^(7/8)*arctan((sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + 2*sqrt(x))/(sqrt(sqrt
(2) + 2)*(a/c)^(1/8)))/(a*c*sqrt(-2*sqrt(2) + 4)) + 7/16*(a/c)^(7/8)*arctan(-(sqrt(-sqrt(2) + 2)*(a/c)^(1/8) -
2*sqrt(x))/(sqrt(sqrt(2) + 2)*(a/c)^(1/8)))/(a*c*sqrt(-2*sqrt(2) + 4)) + 7/16*(a/c)^(7/8)*arctan((sqrt(sqrt(2
) + 2)*(a/c)^(1/8) + 2*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a*c*sqrt(2*sqrt(2) + 4)) + 7/16*(a/c)^(7/8)
*arctan(-(sqrt(sqrt(2) + 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a*c*sqrt(2*sqrt(2) + 4
)) - 7/32*(a/c)^(7/8)*log(sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a*c*sqrt(-2*sqrt(2) + 4))
+ 7/32*(a/c)^(7/8)*log(-sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a*c*sqrt(-2*sqrt(2) + 4)) -
7/32*(a/c)^(7/8)*log(sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a*c*sqrt(2*sqrt(2) + 4)) + 7/3
2*(a/c)^(7/8)*log(-sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a*c*sqrt(2*sqrt(2) + 4))

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maple [C]  time = 0.02, size = 47, normalized size = 0.15 \[ -\frac {x^{\frac {7}{2}}}{4 \left (c \,x^{4}+a \right ) c}+\frac {7 \ln \left (-\RootOf \left (c \,\textit {\_Z}^{8}+a \right )+\sqrt {x}\right )}{32 c^{2} \RootOf \left (c \,\textit {\_Z}^{8}+a \right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(13/2)/(c*x^4+a)^2,x)

[Out]

-1/4*x^(7/2)/c/(c*x^4+a)+7/32/c^2*sum(1/_R*ln(-_R+x^(1/2)),_R=RootOf(_Z^8*c+a))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {x^{\frac {7}{2}}}{4 \, {\left (c^{2} x^{4} + a c\right )}} + 7 \, \int \frac {x^{\frac {5}{2}}}{8 \, {\left (c^{2} x^{4} + a c\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(13/2)/(c*x^4+a)^2,x, algorithm="maxima")

[Out]

-1/4*x^(7/2)/(c^2*x^4 + a*c) + 7*integrate(1/8*x^(5/2)/(c^2*x^4 + a*c), x)

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mupad [B]  time = 0.15, size = 135, normalized size = 0.44 \[ \frac {7\,\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}}{{\left (-a\right )}^{1/8}}\right )}{16\,{\left (-a\right )}^{1/8}\,c^{15/8}}-\frac {x^{7/2}}{4\,c\,\left (c\,x^4+a\right )}+\frac {\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}\,1{}\mathrm {i}}{{\left (-a\right )}^{1/8}}\right )\,7{}\mathrm {i}}{16\,{\left (-a\right )}^{1/8}\,c^{15/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {7}{32}-\frac {7}{32}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}\,c^{15/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {7}{32}+\frac {7}{32}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}\,c^{15/8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(13/2)/(a + c*x^4)^2,x)

[Out]

(7*atan((c^(1/8)*x^(1/2))/(-a)^(1/8)))/(16*(-a)^(1/8)*c^(15/8)) - x^(7/2)/(4*c*(a + c*x^4)) + (atan((c^(1/8)*x
^(1/2)*1i)/(-a)^(1/8))*7i)/(16*(-a)^(1/8)*c^(15/8)) + (2^(1/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 - 1i/2))/(-a
)^(1/8))*(7/32 - 7i/32))/((-a)^(1/8)*c^(15/8)) + (2^(1/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 + 1i/2))/(-a)^(1/
8))*(7/32 + 7i/32))/((-a)^(1/8)*c^(15/8))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(13/2)/(c*x**4+a)**2,x)

[Out]

Timed out

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